0=6x^2-14x-40x

Solution for 0=6x^2-14x-40x equation:

0=6x^2-14x-40x

We move all terms to the left:

0-(6x^2-14x-40x)=0

We add all the numbers together, and all the variables

-(6x^2-14x-40x)=0

We get rid of parentheses

-6x^2+14x+40x=0

We add all the numbers together, and all the variables

-6x^2+54x=0

a = -6; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·(-6)·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*-6}=\frac{-108}{-12}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*-6}=\frac{0}{-12}
=0
$